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1300330220041 is a prime number
BaseRepresentation
bin10010111011000001101…
…110001000101000001001
311121022101020201100222001
4102323001232020220021
5132301034014020131
62433210301231001
7162642252334126
oct22730156105011
94538336640861
101300330220041
11461515567416
12190019b62461
139580b646408
1446d1738774d
1523c57e03261
hex12ec1b88a09

1300330220041 has 2 divisors, whose sum is σ = 1300330220042. Its totient is φ = 1300330220040.

The previous prime is 1300330220003. The next prime is 1300330220087. The reversal of 1300330220041 is 1400220330031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 842028299641 + 458301920400 = 917621^2 + 676980^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300330220041 - 211 = 1300330217993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300330220941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650165110020 + 650165110021.

It is an arithmetic number, because the mean of its divisors is an integer number (650165110021).

Almost surely, 21300330220041 is an apocalyptic number.

It is an amenable number.

1300330220041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300330220041 is an equidigital number, since it uses as much as digits as its factorization.

1300330220041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1300330220041 its reverse (1400220330031), we get a palindrome (2700550550072).

The spelling of 1300330220041 in words is "one trillion, three hundred billion, three hundred thirty million, two hundred twenty thousand, forty-one".