Base | Representation |
---|---|
bin | 100110110000001… |
… | …1001110101000000 |
3 | 10100121211010011221 |
4 | 1031200121311000 |
5 | 10130341340112 |
6 | 333010444424 |
7 | 44136464545 |
oct | 11540316500 |
9 | 3317733157 |
10 | 1300340032 |
11 | 60800a792 |
12 | 303593714 |
13 | 179526994 |
14 | c49acbcc |
15 | 7925ae07 |
hex | 4d819d40 |
1300340032 has 28 divisors (see below), whose sum is σ = 2584091860. Its totient is φ = 649230336.
The previous prime is 1300340011. The next prime is 1300340053. The reversal of 1300340032 is 2300430031.
It is an interprime number because it is at equal distance from previous prime (1300340011) and next prime (1300340053).
It can be written as a sum of positive squares in 2 ways, for example, as 215032896 + 1085307136 = 14664^2 + 32944^2 .
It is a super-2 number, since 2×13003400322 = 3381768397643522048, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a junction number, because it is equal to n+sod(n) for n = 1300339988 and 1300340015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31048 + ... + 59704.
It is an arithmetic number, because the mean of its divisors is an integer number (92288995).
Almost surely, 21300340032 is an apocalyptic number.
It is an amenable number.
1300340032 is a deficient number, since it is larger than the sum of its proper divisors (1283751828).
1300340032 is an equidigital number, since it uses as much as digits as its factorization.
1300340032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29378 (or 29368 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 16.
The square root of 1300340032 is about 36060.2278417649. The cubic root of 1300340032 is about 1091.4880307928.
Adding to 1300340032 its reverse (2300430031), we get a palindrome (3600770063).
It can be divided in two parts, 13003 and 40032, that added together give a palindrome (53035).
The spelling of 1300340032 in words is "one billion, three hundred million, three hundred forty thousand, thirty-two".
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