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130034086541351 = 375913459181361
BaseRepresentation
bin11101100100001111101011…
…100010010111100000100111
3122001102010201001212000000022
4131210033223202113200213
5114020434302123310401
61140320500142505355
736250436612423156
oct3544175342274047
9561363631760008
10130034086541351
1138484167964263
121270158859525b
13577321447c595
14241797d24759d
151007741d3e71b
hex7643eb897827

130034086541351 has 4 divisors (see below), whose sum is σ = 130037545760304. Its totient is φ = 130030627322400.

The previous prime is 130034086541347. The next prime is 130034086541399. The reversal of 130034086541351 is 153145680430031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130034086541351 - 22 = 130034086541347 is a prime.

It is a super-2 number, since 2×1300340865413512 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130034086541321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1729553090 + ... + 1729628271.

It is an arithmetic number, because the mean of its divisors is an integer number (32509386440076).

Almost surely, 2130034086541351 is an apocalyptic number.

130034086541351 is a deficient number, since it is larger than the sum of its proper divisors (3459218953).

130034086541351 is an equidigital number, since it uses as much as digits as its factorization.

130034086541351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3459218952.

The product of its (nonzero) digits is 518400, while the sum is 44.

The spelling of 130034086541351 in words is "one hundred thirty trillion, thirty-four billion, eighty-six million, five hundred forty-one thousand, three hundred fifty-one".

Divisors: 1 37591 3459181361 130034086541351