Base | Representation |
---|---|
bin | 11000001110001000… |
… | …01110111011100111 |
3 | 1020120020021210220100 |
4 | 30013010032323213 |
5 | 203112340432020 |
6 | 5550153035143 |
7 | 640144343112 |
oct | 140704167347 |
9 | 36506253810 |
10 | 13003452135 |
11 | 5573123063 |
12 | 262a9b5ab3 |
13 | 12c301009b |
14 | 8b4dc7579 |
15 | 5118d4a90 |
hex | 30710eee7 |
13003452135 has 12 divisors (see below), whose sum is σ = 22539317112. Its totient is φ = 6935174448.
The previous prime is 13003452131. The next prime is 13003452179. The reversal of 13003452135 is 53125430031.
13003452135 is a `hidden beast` number, since 1 + 300 + 345 + 2 + 13 + 5 = 666.
It is not a de Polignac number, because 13003452135 - 22 = 13003452131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13003452099 and 13003452108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13003452131) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 144482757 + ... + 144482846.
It is an arithmetic number, because the mean of its divisors is an integer number (1878276426).
Almost surely, 213003452135 is an apocalyptic number.
13003452135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13003452135 is a deficient number, since it is larger than the sum of its proper divisors (9535864977).
13003452135 is a wasteful number, since it uses less digits than its factorization.
13003452135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288965614 (or 288965611 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 13003452135 its reverse (53125430031), we get a palindrome (66128882166).
The spelling of 13003452135 in words is "thirteen billion, three million, four hundred fifty-two thousand, one hundred thirty-five".
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