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130035551 is a prime number
BaseRepresentation
bin1111100000000…
…10111101011111
3100001200111020112
413300002331133
5231242114201
620523040235
73136166252
oct760027537
9301614215
10130035551
11674466a8
123767007b
1320c2ba19
14133ad099
15b6390bb
hex7c02f5f

130035551 has 2 divisors, whose sum is σ = 130035552. Its totient is φ = 130035550.

The previous prime is 130035523. The next prime is 130035611. The reversal of 130035551 is 155530031.

It is a weak prime.

It is an emirp because it is prime and its reverse (155530031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130035551 - 214 = 130019167 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130035251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65017775 + 65017776.

It is an arithmetic number, because the mean of its divisors is an integer number (65017776).

Almost surely, 2130035551 is an apocalyptic number.

130035551 is a deficient number, since it is larger than the sum of its proper divisors (1).

130035551 is an equidigital number, since it uses as much as digits as its factorization.

130035551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1125, while the sum is 23.

The square root of 130035551 is about 11403.3131589025. The cubic root of 130035551 is about 506.6258756884.

Adding to 130035551 its reverse (155530031), we get a palindrome (285565582).

The spelling of 130035551 in words is "one hundred thirty million, thirty-five thousand, five hundred fifty-one".