Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1101111001001111110 |
3 | 110102122201110011200102 |
4 | 1321012333233021332 |
5 | 4112310233212342 |
6 | 135423431201102 |
7 | 12252341612630 |
oct | 1710677571176 |
9 | 412581404612 |
10 | 130040132222 |
11 | 501712a0060 |
12 | 21252216192 |
13 | c3552b6600 |
14 | 6418954a50 |
15 | 35b163e832 |
hex | 1e46fef27e |
130040132222 has 96 divisors (see below), whose sum is σ = 269763105024. Its totient is φ = 45626630400.
The previous prime is 130040132221. The next prime is 130040132227. The reversal of 130040132222 is 222231040031.
It is a junction number, because it is equal to n+sod(n) for n = 130040132194 and 130040132203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130040132221) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1006133 + ... + 1127999.
It is an arithmetic number, because the mean of its divisors is an integer number (2810032344).
Almost surely, 2130040132222 is an apocalyptic number.
130040132222 is an abundant number, since it is smaller than the sum of its proper divisors (139722972802).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130040132222 is a wasteful number, since it uses less digits than its factorization.
130040132222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121954 (or 121941 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 130040132222 its reverse (222231040031), we get a palindrome (352271172253).
It can be divided in two parts, 130040 and 132222, that added together give a palindrome (262262).
The spelling of 130040132222 in words is "one hundred thirty billion, forty million, one hundred thirty-two thousand, two hundred twenty-two".
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