13004014141511 has 4 divisors (see below), whose sum is σ = 13249372898952. Its totient is φ = 12758655384072.

The previous prime is 13004014141493. The next prime is 13004014141519. The reversal of 13004014141511 is 11514141040031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13004014141511 is a prime.

It is a super-3 number, since 3×13004014141511³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004014141519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122679378641 + ... + 122679378746.

It is an arithmetic number, because the mean of its divisors is an integer number (3312343224738).

Almost surely, 2^{13004014141511} is an apocalyptic number.

13004014141511 is a deficient number, since it is larger than the sum of its proper divisors (245358757441).

13004014141511 is an equidigital number, since it uses as much as digits as its factorization.

13004014141511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 245358757440.

The product of its (nonzero) digits is 960, while the sum is 26.

Adding to 13004014141511 its reverse (11514141040031), we get a palindrome (24518155181542).

The spelling of 13004014141511 in words is "thirteen trillion, four billion, fourteen million, one hundred forty-one thousand, five hundred eleven".