Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1110001110010011001 |
3 | 110102122201110201110122 |
4 | 1321012333301302121 |
5 | 4112310234034001 |
6 | 135423431323025 |
7 | 12252341656226 |
oct | 1710677616231 |
9 | 412581421418 |
10 | 130040143001 |
11 | 501712a816a |
12 | 21252220475 |
13 | c3552bb4a2 |
14 | 641895894d |
15 | 35b1642b1b |
hex | 1e46ff1c99 |
130040143001 has 4 divisors (see below), whose sum is σ = 130048286004. Its totient is φ = 130032000000.
The previous prime is 130040142979. The next prime is 130040143021. The reversal of 130040143001 is 100341040031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 41952870976 + 88087272025 = 204824^2 + 296795^2 .
It is a cyclic number.
It is not a de Polignac number, because 130040143001 - 26 = 130040142937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130040143021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4047500 + ... + 4079501.
It is an arithmetic number, because the mean of its divisors is an integer number (32512071501).
Almost surely, 2130040143001 is an apocalyptic number.
It is an amenable number.
130040143001 is a deficient number, since it is larger than the sum of its proper divisors (8143003).
130040143001 is an equidigital number, since it uses as much as digits as its factorization.
130040143001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8143002.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130040143001 its reverse (100341040031), we get a palindrome (230381183032).
The spelling of 130040143001 in words is "one hundred thirty billion, forty million, one hundred forty-three thousand, one".
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