1300402120133 has 4 divisors (see below), whose sum is σ = 1300545677280. Its totient is φ = 1300258562988.

The previous prime is 1300402120117. The next prime is 1300402120163. The reversal of 1300402120133 is 3310212040031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300402120133 - 2⁴ = 1300402120117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300402120163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71764985 + ... + 71783102.

It is an arithmetic number, because the mean of its divisors is an integer number (325136419320).

Almost surely, 2^{1300402120133} is an apocalyptic number.

It is an amenable number.

1300402120133 is a deficient number, since it is larger than the sum of its proper divisors (143557147).

1300402120133 is an equidigital number, since it uses as much as digits as its factorization.

1300402120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143557146.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1300402120133 its reverse (3310212040031), we get a palindrome (4610614160164).

The spelling of 1300402120133 in words is "one trillion, three hundred billion, four hundred two million, one hundred twenty thousand, one hundred thirty-three".