1300402120117 has 2 divisors, whose sum is σ = 1300402120118. Its totient is φ = 1300402120116.

The previous prime is 1300402120091. The next prime is 1300402120163. The reversal of 1300402120117 is 7110212040031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1193947397041 + 106454723076 = 1092679^2 + 326274^2 .

It is an emirp because it is prime and its reverse (7110212040031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300402120117 - 2²³ = 1300393731509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300402120177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650201060058 + 650201060059.

It is an arithmetic number, because the mean of its divisors is an integer number (650201060059).

Almost surely, 2^{1300402120117} is an apocalyptic number.

It is an amenable number.

1300402120117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300402120117 is an equidigital number, since it uses as much as digits as its factorization.

1300402120117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 22.

Adding to 1300402120117 its reverse (7110212040031), we get a palindrome (8410614160148).

The spelling of 1300402120117 in words is "one trillion, three hundred billion, four hundred two million, one hundred twenty thousand, one hundred seventeen".