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130040223 = 343346741
BaseRepresentation
bin1111100000001…
…00000110011111
3100001200201122120
413300010012133
5231242241343
620523114023
73136216005
oct760040637
9301621576
10130040223
116744a165
1237672913
1320c30ba1
14133b0a75
15b63a683
hex7c0419f

130040223 has 4 divisors (see below), whose sum is σ = 173386968. Its totient is φ = 86693480.

The previous prime is 130040219. The next prime is 130040243. The reversal of 130040223 is 322040031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130040223 - 22 = 130040219 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130040243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21673368 + ... + 21673373.

It is an arithmetic number, because the mean of its divisors is an integer number (43346742).

Almost surely, 2130040223 is an apocalyptic number.

130040223 is a deficient number, since it is larger than the sum of its proper divisors (43346745).

130040223 is an equidigital number, since it uses as much as digits as its factorization.

130040223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43346744.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 130040223 is about 11403.5180098073. The cubic root of 130040223 is about 506.6319430747.

Adding to 130040223 its reverse (322040031), we get a palindrome (452080254).

The spelling of 130040223 in words is "one hundred thirty million, forty thousand, two hundred twenty-three".

Divisors: 1 3 43346741 130040223