Base | Representation |
---|---|
bin | 111100100011100000… |
… | …0011111110010011101 |
3 | 110102122201211021221011 |
4 | 1321013000133302131 |
5 | 4112310311101141 |
6 | 135423435335221 |
7 | 12252343402450 |
oct | 1710700376235 |
9 | 412581737834 |
10 | 130040331421 |
11 | 50171416790 |
12 | 212522b1511 |
13 | c355356190 |
14 | 64189a7497 |
15 | 35b167d881 |
hex | 1e4701fc9d |
130040331421 has 32 divisors (see below), whose sum is σ = 174642241536. Its totient is φ = 93512664000.
The previous prime is 130040331413. The next prime is 130040331433. The reversal of 130040331421 is 124133040031.
It is not a de Polignac number, because 130040331421 - 23 = 130040331413 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130040331392 and 130040331401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130040331401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4822386 + ... + 4849276.
It is an arithmetic number, because the mean of its divisors is an integer number (5457570048).
Almost surely, 2130040331421 is an apocalyptic number.
130040331421 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
130040331421 is a deficient number, since it is larger than the sum of its proper divisors (44601910115).
130040331421 is a wasteful number, since it uses less digits than its factorization.
130040331421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31753.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 130040331421 its reverse (124133040031), we get a palindrome (254173371452).
The spelling of 130040331421 in words is "one hundred thirty billion, forty million, three hundred thirty-one thousand, four hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •