Base | Representation |
---|---|
bin | 11101100100010101100011… |
… | …111010000111011001011000 |
3 | 122001102202000010121201220001 |
4 | 131210111203322013121120 |
5 | 114021040220124000044 |
6 | 1140323422511342344 |
7 | 36251052235430524 |
oct | 3544254372073130 |
9 | 561382003551801 |
10 | 130040401000024 |
11 | 38486908244549 |
12 | 1270284b2219b4 |
13 | 57739ac739268 |
14 | 2417dbbb10d84 |
15 | 10079b13902d4 |
hex | 764563e87658 |
130040401000024 has 16 divisors (see below), whose sum is σ = 243828843333120. Its totient is φ = 65019376111200.
The previous prime is 130040401000007. The next prime is 130040401000057. The reversal of 130040401000024 is 420000104040031.
It is a junction number, because it is equal to n+sod(n) for n = 130040400999965 and 130040401000010.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102377944 + ... + 103640359.
It is an arithmetic number, because the mean of its divisors is an integer number (15239302708320).
Almost surely, 2130040401000024 is an apocalyptic number.
It is an amenable number.
130040401000024 is a deficient number, since it is larger than the sum of its proper divisors (113788442333096).
130040401000024 is a wasteful number, since it uses less digits than its factorization.
130040401000024 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206097210 (or 206097206 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 130040401000024 its reverse (420000104040031), we get a palindrome (550040505040055).
The spelling of 130040401000024 in words is "one hundred thirty trillion, forty billion, four hundred one million, twenty-four", and thus it is an aban number.
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