13004040221 has 4 divisors (see below), whose sum is σ = 13026814944. Its totient is φ = 12981265500.

The previous prime is 13004040209. The next prime is 13004040223. The reversal of 13004040221 is 12204040031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13004040221 - 2⁶ = 13004040157 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13004040221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004040223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11386505 + ... + 11387646.

It is an arithmetic number, because the mean of its divisors is an integer number (3256703736).

Almost surely, 2^13004040221 is an apocalyptic number.

It is an amenable number.

13004040221 is a deficient number, since it is larger than the sum of its proper divisors (22774723).

13004040221 is an equidigital number, since it uses as much as digits as its factorization.

13004040221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22774722.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 13004040221 its reverse (12204040031), we get a palindrome (25208080252).

The spelling of 13004040221 in words is "thirteen billion, four million, forty thousand, two hundred twenty-one".