1300406131 has 4 divisors (see below), whose sum is σ = 1356945552. Its totient is φ = 1243866712.

The previous prime is 1300406099. The next prime is 1300406141. The reversal of 1300406131 is 1316040031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1316040031 = 97 ⋅13567423.

It is a cyclic number.

It is not a de Polignac number, because 1300406131 - 2⁵ = 1300406099 is a prime.

It is a super-2 number, since 2×1300406131² = 3382112211084778322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300406099 and 1300406108.

It is not an unprimeable number, because it can be changed into a prime (1300406141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28269676 + ... + 28269721.

It is an arithmetic number, because the mean of its divisors is an integer number (339236388).

Almost surely, 2^1300406131 is an apocalyptic number.

1300406131 is a deficient number, since it is larger than the sum of its proper divisors (56539421).

1300406131 is an equidigital number, since it uses as much as digits as its factorization.

1300406131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56539420.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1300406131 is about 36061.1443384705. The cubic root of 1300406131 is about 1091.5065246849.

Adding to 1300406131 its reverse (1316040031), we get a palindrome (2616446162).

The spelling of 1300406131 in words is "one billion, three hundred million, four hundred six thousand, one hundred thirty-one".