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13004112001 = 85715173993
BaseRepresentation
bin11000001110001101…
…10000000010000001
31020120021112100001211
430013012300002001
5203113023041001
65550215130121
7640153061656
oct140706600201
936507470054
1013004112001
115573533901
12262b073941
1312c31b153a
148b5119c2d
155119b5351
hex3071b0081

13004112001 has 4 divisors (see below), whose sum is σ = 13019286852. Its totient is φ = 12988937152.

The previous prime is 13004111977. The next prime is 13004112013. The reversal of 13004112001 is 10021140031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9370433601 + 3633678400 = 96801^2 + 60280^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004112001 - 227 = 12869894273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004112101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7586140 + ... + 7587853.

It is an arithmetic number, because the mean of its divisors is an integer number (3254821713).

Almost surely, 213004112001 is an apocalyptic number.

It is an amenable number.

13004112001 is a deficient number, since it is larger than the sum of its proper divisors (15174851).

13004112001 is an equidigital number, since it uses as much as digits as its factorization.

13004112001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15174850.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 13004112001 its reverse (10021140031), we get a palindrome (23025252032).

The spelling of 13004112001 in words is "thirteen billion, four million, one hundred twelve thousand, one".

Divisors: 1 857 15173993 13004112001