1300412540848 has 20 divisors (see below), whose sum is σ = 2667758080680. Its totient is φ = 611958842624.

The previous prime is 1300412540771. The next prime is 1300412540873. The reversal of 1300412540848 is 8480452140031.

It is a self number, because there is not a number n which added to its sum of digits gives 1300412540848.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2390463958 + ... + 2390464501.

It is an arithmetic number, because the mean of its divisors is an integer number (133387904034).

Almost surely, 2^{1300412540848} is an apocalyptic number.

It is an amenable number.

1300412540848 is an abundant number, since it is smaller than the sum of its proper divisors (1367345539832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300412540848 is a wasteful number, since it uses less digits than its factorization.

1300412540848 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4780928484 (or 4780928478 counting only the distinct ones).

The product of its (nonzero) digits is 122880, while the sum is 40.

Adding to 1300412540848 its reverse (8480452140031), we get a palindrome (9780864680879).

The spelling of 1300412540848 in words is "one trillion, three hundred billion, four hundred twelve million, five hundred forty thousand, eight hundred forty-eight".