13004125471 has 2 divisors, whose sum is σ = 13004125472. Its totient is φ = 13004125470.

The previous prime is 13004125447. The next prime is 13004125499. The reversal of 13004125471 is 17452140031.

It is an a-pointer prime, because the next prime (13004125499) can be obtained adding 13004125471 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13004125471 - 2¹¹ = 13004123423 is a prime.

It is a super-3 number, since 3×13004125471³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13004125271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502062735 + 6502062736.

It is an arithmetic number, because the mean of its divisors is an integer number (6502062736).

Almost surely, 2^13004125471 is an apocalyptic number.

13004125471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004125471 is an equidigital number, since it uses as much as digits as its factorization.

13004125471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 28.

The spelling of 13004125471 in words is "thirteen billion, four million, one hundred twenty-five thousand, four hundred seventy-one".