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13004140300 = 2252130041403
BaseRepresentation
bin11000001110001101…
…10110111100001100
31020120021120202212221
430013012312330030
5203113024442200
65550215505124
7640153240324
oct140706667414
936507522787
1013004140300
115573553098
12262b0881a4
1312c31c1398
148b5126284
155119bd91a
hex3071b6f0c

13004140300 has 18 divisors (see below), whose sum is σ = 28218984668. Its totient is φ = 5201656080.

The previous prime is 13004140249. The next prime is 13004140321. The reversal of 13004140300 is 304140031.

13004140300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65020602 + ... + 65020801.

Almost surely, 213004140300 is an apocalyptic number.

13004140300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13004140300 is an abundant number, since it is smaller than the sum of its proper divisors (15214844368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004140300 is a wasteful number, since it uses less digits than its factorization.

13004140300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130041417 (or 130041410 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 13004140300 its reverse (304140031), we get a palindrome (13308280331).

The spelling of 13004140300 in words is "thirteen billion, four million, one hundred forty thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 130041403 260082806 520165612 650207015 1300414030 2600828060 3251035075 6502070150 13004140300