Search a number
-
+
1300420111 = 4727668513
BaseRepresentation
bin100110110000010…
…1101011000001111
310100121222012000211
41031200231120033
510130401420421
6333012303251
744140250164
oct11540553017
93317865024
101300420111
11608064971
12303611b27
13179554273
14c49d006b
15792749e1
hex4d82d60f

1300420111 has 4 divisors (see below), whose sum is σ = 1328088672. Its totient is φ = 1272751552.

The previous prime is 1300420109. The next prime is 1300420123. The reversal of 1300420111 is 1110240031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300420111 - 21 = 1300420109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300420091 and 1300420100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300420171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13834210 + ... + 13834303.

It is an arithmetic number, because the mean of its divisors is an integer number (332022168).

Almost surely, 21300420111 is an apocalyptic number.

1300420111 is a deficient number, since it is larger than the sum of its proper divisors (27668561).

1300420111 is an equidigital number, since it uses as much as digits as its factorization.

1300420111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27668560.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1300420111 is about 36061.3381753922. The cubic root of 1300420111 is about 1091.5104360800.

Adding to 1300420111 its reverse (1110240031), we get a palindrome (2410660142).

The spelling of 1300420111 in words is "one billion, three hundred million, four hundred twenty thousand, one hundred eleven".

Divisors: 1 47 27668513 1300420111