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1300420245 = 3586694683
BaseRepresentation
bin100110110000010…
…1101011010010101
310100121222012012210
41031200231122111
510130401421440
6333012304033
744140250445
oct11540553225
93317865183
101300420245
11608064a83
12303612019
13179554347
14c49d0125
1579274a80
hex4d82d695

1300420245 has 8 divisors (see below), whose sum is σ = 2080672416. Its totient is φ = 693557456.

The previous prime is 1300420223. The next prime is 1300420259. The reversal of 1300420245 is 5420240031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300420245 - 25 = 1300420213 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43347327 + ... + 43347356.

It is an arithmetic number, because the mean of its divisors is an integer number (260084052).

Almost surely, 21300420245 is an apocalyptic number.

1300420245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1300420245 is a deficient number, since it is larger than the sum of its proper divisors (780252171).

1300420245 is an equidigital number, since it uses as much as digits as its factorization.

1300420245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86694691.

The product of its (nonzero) digits is 960, while the sum is 21.

The square root of 1300420245 is about 36061.3400333376. The cubic root of 1300420245 is about 1091.5104735711.

Adding to 1300420245 its reverse (5420240031), we get a palindrome (6720660276).

The spelling of 1300420245 in words is "one billion, three hundred million, four hundred twenty thousand, two hundred forty-five".

Divisors: 1 3 5 15 86694683 260084049 433473415 1300420245