Base | Representation |
---|---|
bin | 11000001110001110… |
… | …01000000000111011 |
3 | 1020120021201022211010 |
4 | 30013013020000323 |
5 | 203113034211420 |
6 | 5550221205003 |
7 | 640153651242 |
oct | 140707100073 |
9 | 36507638733 |
10 | 13004210235 |
11 | 55735a0695 |
12 | 262b100763 |
13 | 12c3217173 |
14 | 8b5143959 |
15 | 5119d44e0 |
hex | 3071c803b |
13004210235 has 16 divisors (see below), whose sum is σ = 21711377664. Its totient is φ = 6634031712.
The previous prime is 13004210203. The next prime is 13004210249. The reversal of 13004210235 is 53201240031.
It is not a de Polignac number, because 13004210235 - 25 = 13004210203 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18846337 + ... + 18847026.
It is an arithmetic number, because the mean of its divisors is an integer number (1356961104).
Almost surely, 213004210235 is an apocalyptic number.
13004210235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13004210235 is a deficient number, since it is larger than the sum of its proper divisors (8707167429).
13004210235 is a wasteful number, since it uses less digits than its factorization.
13004210235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37693394.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 13004210235 its reverse (53201240031), we get a palindrome (66205450266).
The spelling of 13004210235 in words is "thirteen billion, four million, two hundred ten thousand, two hundred thirty-five".
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