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13004243153 = 117511574173
BaseRepresentation
bin11000001110001110…
…10000000011010001
31020120021202222222022
430013013100003101
5203113041240103
65550222021225
7640154146226
oct140707200321
936507688868
1013004243153
1155736133a0
12262b117815
1312c3229145
148b515194d
155119de138
hex3071d00d1

13004243153 has 8 divisors (see below), whose sum is σ = 14205346176. Its totient is φ = 11806290000.

The previous prime is 13004243129. The next prime is 13004243209. The reversal of 13004243153 is 35134240031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004243153 - 26 = 13004243089 is a prime.

It is a super-2 number, since 2×130042431532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004243353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 778826 + ... + 795347.

It is an arithmetic number, because the mean of its divisors is an integer number (1775668272).

Almost surely, 213004243153 is an apocalyptic number.

It is an amenable number.

13004243153 is a deficient number, since it is larger than the sum of its proper divisors (1201103023).

13004243153 is a wasteful number, since it uses less digits than its factorization.

13004243153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1574935.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 13004243153 its reverse (35134240031), we get a palindrome (48138483184).

The spelling of 13004243153 in words is "thirteen billion, four million, two hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 11 751 8261 1574173 17315903 1182203923 13004243153