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13004256351719 = 97713310395447
BaseRepresentation
bin1011110100111100101000…
…0101001001010111100111
31201001012020222120121011202
42331033022011021113213
53201030204111223334
643354023424553115
72511345411113153
oct275171205112747
951035228517152
1013004256351719
11416408a765846
12156038b18279b
137343b0734629
1432d5a342a063
1517840d19817e
hexbd3ca1495e7

13004256351719 has 4 divisors (see below), whose sum is σ = 13017566748144. Its totient is φ = 12990945955296.

The previous prime is 13004256351673. The next prime is 13004256351739. The reversal of 13004256351719 is 91715365240031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13004256351719 - 212 = 13004256347623 is a prime.

It is a super-2 number, since 2×130042563517192 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004256351739) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6655196747 + ... + 6655198700.

It is an arithmetic number, because the mean of its divisors is an integer number (3254391687036).

Almost surely, 213004256351719 is an apocalyptic number.

13004256351719 is a deficient number, since it is larger than the sum of its proper divisors (13310396425).

13004256351719 is an equidigital number, since it uses as much as digits as its factorization.

13004256351719 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13310396424.

The product of its (nonzero) digits is 680400, while the sum is 47.

The spelling of 13004256351719 in words is "thirteen trillion, four billion, two hundred fifty-six million, three hundred fifty-one thousand, seven hundred nineteen".

Divisors: 1 977 13310395447 13004256351719