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13004304143 = 70489184487
BaseRepresentation
bin11000001110001110…
…11110111100001111
31020120021220002122012
430013013132330033
5203113100213033
65550223211435
7640154522105
oct140707367417
936507802565
1013004304143
1155736551a6
12262b146b7b
1312c324ab2c
148b5169c75
15511a02248
hex3071def0f

13004304143 has 4 divisors (see below), whose sum is σ = 13004559120. Its totient is φ = 13004049168.

The previous prime is 13004304119. The next prime is 13004304199. The reversal of 13004304143 is 34140340031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34140340031 = 74877191433.

It is a cyclic number.

It is not a de Polignac number, because 13004304143 - 222 = 13000109839 is a prime.

It is a super-2 number, since 2×130043041432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004304113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21755 + ... + 162732.

It is an arithmetic number, because the mean of its divisors is an integer number (3251139780).

Almost surely, 213004304143 is an apocalyptic number.

13004304143 is a deficient number, since it is larger than the sum of its proper divisors (254977).

13004304143 is an equidigital number, since it uses as much as digits as its factorization.

13004304143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 254976.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13004304143 its reverse (34140340031), we get a palindrome (47144644174).

The spelling of 13004304143 in words is "thirteen billion, four million, three hundred four thousand, one hundred forty-three".

Divisors: 1 70489 184487 13004304143