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1300431001 = 6121318541
BaseRepresentation
bin100110110000011…
…0000000010011001
310100121222201222011
41031200300002121
510130402243001
6333012425521
744140324012
oct11540600231
93317881864
101300431001
11608072071
123036182a1
131795591cc
14c49d4009
1579277d51
hex4d830099

1300431001 has 4 divisors (see below), whose sum is σ = 1321749604. Its totient is φ = 1279112400.

The previous prime is 1300430993. The next prime is 1300431019. The reversal of 1300431001 is 1001340031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1001340031 = 1033396907.

It can be written as a sum of positive squares in 2 ways, for example, as 273869401 + 1026561600 = 16549^2 + 32040^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300431001 - 23 = 1300430993 is a prime.

It is a super-2 number, since 2×13004310012 = 3382241576723724002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300431091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10659210 + ... + 10659331.

It is an arithmetic number, because the mean of its divisors is an integer number (330437401).

Almost surely, 21300431001 is an apocalyptic number.

It is an amenable number.

1300431001 is a deficient number, since it is larger than the sum of its proper divisors (21318603).

1300431001 is an equidigital number, since it uses as much as digits as its factorization.

1300431001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21318602.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1300431001 is about 36061.4891678089. The cubic root of 1300431001 is about 1091.5134829199.

Adding to 1300431001 its reverse (1001340031), we get a palindrome (2301771032).

It can be divided in two parts, 130043 and 1001, that added together give a square (131044 = 3622).

The spelling of 1300431001 in words is "one billion, three hundred million, four hundred thirty-one thousand, one".

Divisors: 1 61 21318541 1300431001