1300434132 has 24 divisors (see below), whose sum is σ = 3035326336. Its totient is φ = 433338048.

The previous prime is 1300434131. The next prime is 1300434151. The reversal of 1300434132 is 2314340031.

It is a super-2 number, since 2×1300434132² = 3382257863341186848, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300434099 and 1300434108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300434131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25413 + ... + 56979.

Almost surely, 2^1300434132 is an apocalyptic number.

1300434132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1300434132 is an abundant number, since it is smaller than the sum of its proper divisors (1734892204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300434132 is a wasteful number, since it uses less digits than its factorization.

1300434132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35007 (or 35005 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 21.

The square root of 1300434132 is about 36061.5325797449. The cubic root of 1300434132 is about 1091.5143589181.

Adding to 1300434132 its reverse (2314340031), we get a palindrome (3614774163).

The spelling of 1300434132 in words is "one billion, three hundred million, four hundred thirty-four thousand, one hundred thirty-two".