Base | Representation |
---|---|
bin | 100110110000011… |
… | …0010001110101101 |
3 | 10100122000012021202 |
4 | 1031200302032231 |
5 | 10130403034411 |
6 | 333012535245 |
7 | 44140362131 |
oct | 11540621655 |
9 | 3318005252 |
10 | 1300439981 |
11 | 608078895 |
12 | 303621525 |
13 | 179560319 |
14 | c49d73c1 |
15 | 7927a83b |
hex | 4d8323ad |
1300439981 has 2 divisors, whose sum is σ = 1300439982. Its totient is φ = 1300439980.
The previous prime is 1300439963. The next prime is 1300440017. The reversal of 1300439981 is 1899340031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1146431881 + 154008100 = 33859^2 + 12410^2 .
It is an emirp because it is prime and its reverse (1899340031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1300439981 - 222 = 1296245677 is a prime.
It is a super-2 number, since 2×13004399812 = 3382288288366560722, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300439081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650219990 + 650219991.
It is an arithmetic number, because the mean of its divisors is an integer number (650219991).
Almost surely, 21300439981 is an apocalyptic number.
It is an amenable number.
1300439981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300439981 is an equidigital number, since it uses as much as digits as its factorization.
1300439981 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 38.
The square root of 1300439981 is about 36061.6136771498. The cubic root of 1300439981 is about 1091.5159953609.
The spelling of 1300439981 in words is "one billion, three hundred million, four hundred thirty-nine thousand, nine hundred eighty-one".
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