1300441111111 has 2 divisors, whose sum is σ = 1300441111112. Its totient is φ = 1300441111110.

The previous prime is 1300441111097. The next prime is 1300441111127. The reversal of 1300441111111 is 1111111440031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300441111111 is a prime.

It is a super-2 number, since 2×1300441111111² (a number of 25 digits) contains 22 as substring.

1300441111111 is a modest number, since divided by 1111111 gives 130044 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300441111511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650220555555 + 650220555556.

It is an arithmetic number, because the mean of its divisors is an integer number (650220555556).

Almost surely, 2^{1300441111111} is an apocalyptic number.

1300441111111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300441111111 is an equidigital number, since it uses as much as digits as its factorization.

1300441111111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1300441111111 its reverse (1111111440031), we get a palindrome (2411552551142).

The spelling of 1300441111111 in words is "one trillion, three hundred billion, four hundred forty-one million, one hundred eleven thousand, one hundred eleven".