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130044203 = 1738319973
BaseRepresentation
bin1111100000001…
…01000100101011
3100001200221002222
413300011010223
5231242403303
620523144255
73136233422
oct760050453
9301627088
10130044203
1167452153
123767508b
1320c32943
14133b22b9
15b63b938
hex7c0512b

130044203 has 8 divisors (see below), whose sum is σ = 138060288. Its totient is φ = 122068864.

The previous prime is 130044193. The next prime is 130044209. The reversal of 130044203 is 302440031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130044203 - 212 = 130040107 is a prime.

It is a super-2 number, since 2×1300442032 = 33822989467810418, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130044209) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3476 + ... + 16497.

It is an arithmetic number, because the mean of its divisors is an integer number (17257536).

Almost surely, 2130044203 is an apocalyptic number.

130044203 is a deficient number, since it is larger than the sum of its proper divisors (8016085).

130044203 is a wasteful number, since it uses less digits than its factorization.

130044203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20373.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 130044203 is about 11403.6925160230. The cubic root of 130044203 is about 506.6371116667.

Adding to 130044203 its reverse (302440031), we get a palindrome (432484234).

The spelling of 130044203 in words is "one hundred thirty million, forty-four thousand, two hundred three".

Divisors: 1 17 383 6511 19973 339541 7649659 130044203