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13004423132431 = 31419497520401
BaseRepresentation
bin1011110100111101010000…
…0001010111010100001111
31201001012200121101221022011
42331033110001113110033
53201031024310214211
643354052143402051
72511352504533253
oct275172401272417
951035617357264
1013004423132431
114164165919645
121560416bb3327
1373440915a543
1432d5bb642263
1517841cb3e921
hexbd3d405750f

13004423132431 has 4 divisors (see below), whose sum is σ = 13423920652864. Its totient is φ = 12584925612000.

The previous prime is 13004423132429. The next prime is 13004423132447. The reversal of 13004423132431 is 13423132440031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13004423132431 - 21 = 13004423132429 is a prime.

It is a super-2 number, since 2×130044231324312 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 419497520401 = 13004423132431 / (1 + 3 + 0 + 0 + 4 + 4 + 2 + 3 + 1 + 3 + 2 + 4 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13004423132393 and 13004423132402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004423132401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209748760170 + ... + 209748760231.

It is an arithmetic number, because the mean of its divisors is an integer number (3355980163216).

Almost surely, 213004423132431 is an apocalyptic number.

13004423132431 is a deficient number, since it is larger than the sum of its proper divisors (419497520433).

13004423132431 is an equidigital number, since it uses as much as digits as its factorization.

13004423132431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419497520432.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13004423132431 its reverse (13423132440031), we get a palindrome (26427555572462).

The spelling of 13004423132431 in words is "thirteen trillion, four billion, four hundred twenty-three million, one hundred thirty-two thousand, four hundred thirty-one".

Divisors: 1 31 419497520401 13004423132431