Base | Representation |
---|---|
bin | 11000001110010000… |
… | …00010101001101101 |
3 | 1020120022011112021121 |
4 | 30013020002221231 |
5 | 203113114403123 |
6 | 5550230300541 |
7 | 640156001413 |
oct | 140710025155 |
9 | 36508145247 |
10 | 13004450413 |
11 | 5573745089 |
12 | 262b1b7751 |
13 | 12c329c596 |
14 | 8b51a72b3 |
15 | 511a3075d |
hex | 307202a6d |
13004450413 has 2 divisors, whose sum is σ = 13004450414. Its totient is φ = 13004450412.
The previous prime is 13004450411. The next prime is 13004450443. The reversal of 13004450413 is 31405440031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11872935369 + 1131515044 = 108963^2 + 33638^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004450413 - 21 = 13004450411 is a prime.
Together with 13004450411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004450411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502225206 + 6502225207.
It is an arithmetic number, because the mean of its divisors is an integer number (6502225207).
Almost surely, 213004450413 is an apocalyptic number.
It is an amenable number.
13004450413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004450413 is an equidigital number, since it uses as much as digits as its factorization.
13004450413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 13004450413 its reverse (31405440031), we get a palindrome (44409890444).
The spelling of 13004450413 in words is "thirteen billion, four million, four hundred fifty thousand, four hundred thirteen".
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