Base | Representation |
---|---|
bin | 11000001110010000… |
… | …00011001100101011 |
3 | 1020120022011122100111 |
4 | 30013020003030223 |
5 | 203113114441101 |
6 | 5550230315151 |
7 | 640156011061 |
oct | 140710031453 |
9 | 36508148314 |
10 | 13004452651 |
11 | 5573746833 |
12 | 262b1b8ab7 |
13 | 12c32a05c8 |
14 | 8b51a8031 |
15 | 511a31251 |
hex | 30720332b |
13004452651 has 8 divisors (see below), whose sum is σ = 13958043984. Its totient is φ = 12071819520.
The previous prime is 13004452649. The next prime is 13004452711. The reversal of 13004452651 is 15625440031.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13004452651 - 21 = 13004452649 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13004450651) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5238265 + ... + 5240746.
It is an arithmetic number, because the mean of its divisors is an integer number (1744755498).
Almost surely, 213004452651 is an apocalyptic number.
13004452651 is a deficient number, since it is larger than the sum of its proper divisors (953591333).
13004452651 is a wasteful number, since it uses less digits than its factorization.
13004452651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10479101.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13004452651 its reverse (15625440031), we get a palindrome (28629892682).
The spelling of 13004452651 in words is "thirteen billion, four million, four hundred fifty-two thousand, six hundred fifty-one".
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