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130044541001 = 401324300601
BaseRepresentation
bin111100100011101000…
…0100011100001001001
3110102200000202011101112
41321013100203201021
54112312400303001
6135424105500105
712252424234334
oct1710720434111
9412600664345
10130044541001
1150173831481
12212537a1635
13c35619b25b
14641938161b
1535b1c10cbb
hex1e47423849

130044541001 has 4 divisors (see below), whose sum is σ = 130368842004. Its totient is φ = 129720240000.

The previous prime is 130044540979. The next prime is 130044541019. The reversal of 130044541001 is 100145440031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 109716625225 + 20327915776 = 331235^2 + 142576^2 .

It is a cyclic number.

It is not a de Polignac number, because 130044541001 - 218 = 130044278857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130044541021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162149900 + ... + 162150701.

It is an arithmetic number, because the mean of its divisors is an integer number (32592210501).

Almost surely, 2130044541001 is an apocalyptic number.

It is an amenable number.

130044541001 is a deficient number, since it is larger than the sum of its proper divisors (324301003).

130044541001 is an equidigital number, since it uses as much as digits as its factorization.

130044541001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 324301002.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 130044541001 its reverse (100145440031), we get a palindrome (230189981032).

The spelling of 130044541001 in words is "one hundred thirty billion, forty-four million, five hundred forty-one thousand, one".

Divisors: 1 401 324300601 130044541001