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130048527513589 is a prime number
BaseRepresentation
bin11101100100011101001000…
…010010010011011111110101
3122001110111222111002101202221
4131210131020102103133311
5114021203341020413324
61140331245131002341
736251460513601066
oct3544351022233765
9561414874071687
10130048527513589
113848a2a8472463
12127043388993b1
1357746a6246c79
14241854d10c56d
151007cd9a2b0e4
hex7647484937f5

130048527513589 has 2 divisors, whose sum is σ = 130048527513590. Its totient is φ = 130048527513588.

The previous prime is 130048527513547. The next prime is 130048527513623. The reversal of 130048527513589 is 985315725840031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77213917251025 + 52834610262564 = 8787145^2 + 7268742^2 .

It is an emirp because it is prime and its reverse (985315725840031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130048527513589 - 219 = 130048526989301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130048527513539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65024263756794 + 65024263756795.

It is an arithmetic number, because the mean of its divisors is an integer number (65024263756795).

Almost surely, 2130048527513589 is an apocalyptic number.

It is an amenable number.

130048527513589 is a deficient number, since it is larger than the sum of its proper divisors (1).

130048527513589 is an equidigital number, since it uses as much as digits as its factorization.

130048527513589 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288000, while the sum is 61.

The spelling of 130048527513589 in words is "one hundred thirty trillion, forty-eight billion, five hundred twenty-seven million, five hundred thirteen thousand, five hundred eighty-nine".