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130048527513623 is a prime number
BaseRepresentation
bin11101100100011101001000…
…010010010011100000010111
3122001110111222111002101211012
4131210131020102103200113
5114021203341020413443
61140331245131002435
736251460513601145
oct3544351022234027
9561414874071735
10130048527513623
113848a2a8472494
121270433889941b
1357746a6246ca4
14241854d10c595
151007cd9a2b118
hex764748493817

130048527513623 has 2 divisors, whose sum is σ = 130048527513624. Its totient is φ = 130048527513622.

The previous prime is 130048527513589. The next prime is 130048527513649. The reversal of 130048527513623 is 326315725840031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130048527513623 - 218 = 130048527251479 is a prime.

It is a super-2 number, since 2×1300485275136232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130048527513683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65024263756811 + 65024263756812.

It is an arithmetic number, because the mean of its divisors is an integer number (65024263756812).

Almost surely, 2130048527513623 is an apocalyptic number.

130048527513623 is a deficient number, since it is larger than the sum of its proper divisors (1).

130048527513623 is an equidigital number, since it uses as much as digits as its factorization.

130048527513623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3628800, while the sum is 50.

The spelling of 130048527513623 in words is "one hundred thirty trillion, forty-eight billion, five hundred twenty-seven million, five hundred thirteen thousand, six hundred twenty-three".