Base | Representation |
---|---|
bin | 111100100011110011… |
… | …1011101000111011101 |
3 | 110102200110001011002021 |
4 | 1321013213131013131 |
5 | 4112320414402333 |
6 | 135424442300141 |
7 | 12252526246141 |
oct | 1710747350735 |
9 | 412613034067 |
10 | 130050544093 |
11 | 50177161708 |
12 | 212557b7651 |
13 | c3574c0792 |
14 | 641a0a5221 |
15 | 35b24e982d |
hex | 1e479dd1dd |
130050544093 has 2 divisors, whose sum is σ = 130050544094. Its totient is φ = 130050544092.
The previous prime is 130050544069. The next prime is 130050544147. The reversal of 130050544093 is 390445050031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108400953049 + 21649591044 = 329243^2 + 147138^2 .
It is a cyclic number.
It is not a de Polignac number, because 130050544093 - 229 = 129513673181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130050544003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65025272046 + 65025272047.
It is an arithmetic number, because the mean of its divisors is an integer number (65025272047).
Almost surely, 2130050544093 is an apocalyptic number.
It is an amenable number.
130050544093 is a deficient number, since it is larger than the sum of its proper divisors (1).
130050544093 is an equidigital number, since it uses as much as digits as its factorization.
130050544093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 130050544093 in words is "one hundred thirty billion, fifty million, five hundred forty-four thousand, ninety-three".
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