13005115403 has 4 divisors (see below), whose sum is σ = 14862989040. Its totient is φ = 11147241768.

The previous prime is 13005115399. The next prime is 13005115433. The reversal of 13005115403 is 30451150031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30451150031 = 71411 ⋅426421.

It is a cyclic number.

It is not a de Polignac number, because 13005115403 - 2² = 13005115399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13005115433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 928936808 + ... + 928936821.

It is an arithmetic number, because the mean of its divisors is an integer number (3715747260).

Almost surely, 2^13005115403 is an apocalyptic number.

13005115403 is a deficient number, since it is larger than the sum of its proper divisors (1857873637).

13005115403 is an equidigital number, since it uses as much as digits as its factorization.

13005115403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1857873636.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 13005115403 its reverse (30451150031), we get a palindrome (43456265434).

The spelling of 13005115403 in words is "thirteen billion, five million, one hundred fifteen thousand, four hundred three".