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13005121 is a prime number
BaseRepresentation
bin110001100111…
…000101000001
3220110201200011
4301213011001
511312130441
61142424521
7215353543
oct61470501
926421604
1013005121
117382a38
124432141
13290464c
141a27693
15121d581
hexc67141

13005121 has 2 divisors, whose sum is σ = 13005122. Its totient is φ = 13005120.

The previous prime is 13005103. The next prime is 13005127. The reversal of 13005121 is 12150031.

13005121 = T2943 + T2944 + T2945.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11806096 + 1199025 = 3436^2 + 1095^2 .

It is an emirp because it is prime and its reverse (12150031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13005121 - 27 = 13004993 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13005127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502560 + 6502561.

It is an arithmetic number, because the mean of its divisors is an integer number (6502561).

Almost surely, 213005121 is an apocalyptic number.

13005121 is the 2945-th centered triangular number.

It is an amenable number.

13005121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13005121 is an equidigital number, since it uses as much as digits as its factorization.

13005121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 13005121 is about 3606.2613604674. The cubic root of 13005121 is about 235.1643395520.

Adding to 13005121 its reverse (12150031), we get a palindrome (25155152).

The spelling of 13005121 in words is "thirteen million, five thousand, one hundred twenty-one".