Base | Representation |
---|---|
bin | 11101100100011111101111… |
… | …000010101000101110011001 |
3 | 122001110210012110102122211111 |
4 | 131210133233002220232121 |
5 | 114021230103222420210 |
6 | 1140332430511100321 |
7 | 36251620034546044 |
oct | 3544375702505631 |
9 | 561423173378744 |
10 | 130051325201305 |
11 | 38490503710672 |
12 | 127049998116a1 |
13 | 5774a30a448a1 |
14 | 24187368cdc5b |
15 | 1007e0045a88a |
hex | 7647ef0a8b99 |
130051325201305 has 16 divisors (see below), whose sum is σ = 162847717799040. Its totient is φ = 99517021846528.
The previous prime is 130051325201299. The next prime is 130051325201309. The reversal of 130051325201305 is 503102523150031.
It is a cyclic number.
It is not a de Polignac number, because 130051325201305 - 23 = 130051325201297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130051325201309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20239026 + ... + 25878964.
It is an arithmetic number, because the mean of its divisors is an integer number (10177982362440).
Almost surely, 2130051325201305 is an apocalyptic number.
It is an amenable number.
130051325201305 is a deficient number, since it is larger than the sum of its proper divisors (32796392597735).
130051325201305 is a wasteful number, since it uses less digits than its factorization.
130051325201305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5840480.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 130051325201305 its reverse (503102523150031), we get a palindrome (633153848351336).
The spelling of 130051325201305 in words is "one hundred thirty trillion, fifty-one billion, three hundred twenty-five million, two hundred one thousand, three hundred five".
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