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13005223423 = 64720100809
BaseRepresentation
bin11000001110010101…
…11111010111111111
31020120100121210122121
430013022333113333
5203113314122143
65550255023411
7640165401163
oct140712772777
936510553577
1013005223423
115574122935
12262b50ab67
1312c34b039a
148b5328ca3
15511b347ed
hex3072bf5ff

13005223423 has 4 divisors (see below), whose sum is σ = 13025324880. Its totient is φ = 12985121968.

The previous prime is 13005223393. The next prime is 13005223453. The reversal of 13005223423 is 32432250031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13005223393) and next prime (13005223453).

It is a cyclic number.

It is not a de Polignac number, because 13005223423 - 221 = 13003126271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13005223453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10049758 + ... + 10051051.

It is an arithmetic number, because the mean of its divisors is an integer number (3256331220).

Almost surely, 213005223423 is an apocalyptic number.

13005223423 is a deficient number, since it is larger than the sum of its proper divisors (20101457).

13005223423 is an equidigital number, since it uses as much as digits as its factorization.

13005223423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20101456.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 13005223423 its reverse (32432250031), we get a palindrome (45437473454).

The spelling of 13005223423 in words is "thirteen billion, five million, two hundred twenty-three thousand, four hundred twenty-three".

Divisors: 1 647 20100809 13005223423