Base | Representation |
---|---|
bin | 11000001110011000… |
… | …10010110010101111 |
3 | 1020120101021011100102 |
4 | 30013030102302233 |
5 | 203113411040403 |
6 | 5550310221315 |
7 | 640201323266 |
oct | 140714226257 |
9 | 36511234312 |
10 | 13005565103 |
11 | 5574336613 |
12 | 262b65483b |
13 | 12c359ca6b |
14 | 8b53b75dd |
15 | 511ba0b88 |
hex | 307312caf |
13005565103 has 2 divisors, whose sum is σ = 13005565104. Its totient is φ = 13005565102.
The previous prime is 13005565081. The next prime is 13005565117. The reversal of 13005565103 is 30156550031.
13005565103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13005565103 - 216 = 13005499567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13005565123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502782551 + 6502782552.
It is an arithmetic number, because the mean of its divisors is an integer number (6502782552).
Almost surely, 213005565103 is an apocalyptic number.
13005565103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13005565103 is an equidigital number, since it uses as much as digits as its factorization.
13005565103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6750, while the sum is 29.
The spelling of 13005565103 in words is "thirteen billion, five million, five hundred sixty-five thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •