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130062524653 = 373515203369
BaseRepresentation
bin111100100100001010…
…1001010000011101101
3110102201021120211022201
41321020111022003231
54112332001242103
6135425551141501
712253033134655
oct1711025120355
9412637524281
10130062524653
11501829a48a6
1221259814891
13c359b26979
14641b903365
1535b35b451d
hex1e4854a0ed

130062524653 has 4 divisors (see below), whose sum is σ = 133577728060. Its totient is φ = 126547321248.

The previous prime is 130062524629. The next prime is 130062524663. The reversal of 130062524653 is 356425260031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 356425260031 = 1632186658037.

It can be written as a sum of positive squares in 2 ways, for example, as 75033809929 + 55028714724 = 273923^2 + 234582^2 .

It is a cyclic number.

It is not a de Polignac number, because 130062524653 - 221 = 130060427501 is a prime.

It is a super-2 number, since 2×1300625246532 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (37), and also a Moran number because the ratio is a prime number: 3515203369 = 130062524653 / (1 + 3 + 0 + 0 + 6 + 2 + 5 + 2 + 4 + 6 + 5 + 3).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130062524623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1757601648 + ... + 1757601721.

It is an arithmetic number, because the mean of its divisors is an integer number (33394432015).

Almost surely, 2130062524653 is an apocalyptic number.

It is an amenable number.

130062524653 is a deficient number, since it is larger than the sum of its proper divisors (3515203407).

130062524653 is an equidigital number, since it uses as much as digits as its factorization.

130062524653 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3515203406.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 130062524653 its reverse (356425260031), we get a palindrome (486487784684).

The spelling of 130062524653 in words is "one hundred thirty billion, sixty-two million, five hundred twenty-four thousand, six hundred fifty-three".

Divisors: 1 37 3515203369 130062524653