Base | Representation |
---|---|
bin | 11000001110110001… |
… | …10011010110001101 |
3 | 1020120121102202101110 |
4 | 30013120303112031 |
5 | 203120231003143 |
6 | 5550504402233 |
7 | 640241231253 |
oct | 140730632615 |
9 | 36517382343 |
10 | 13008844173 |
11 | 5576176196 |
12 | 2630776379 |
13 | 12c417a440 |
14 | 8b59cc5d3 |
15 | 5120ec533 |
hex | 30763358d |
13008844173 has 16 divisors (see below), whose sum is σ = 18813757760. Its totient is φ = 7947846144.
The previous prime is 13008844169. The next prime is 13008844187. The reversal of 13008844173 is 37144880031.
13008844173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13008844173 - 22 = 13008844169 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13008844973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1194436 + ... + 1205277.
It is an arithmetic number, because the mean of its divisors is an integer number (1175859860).
Almost surely, 213008844173 is an apocalyptic number.
13008844173 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13008844173 is a deficient number, since it is larger than the sum of its proper divisors (5804913587).
13008844173 is a wasteful number, since it uses less digits than its factorization.
13008844173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2399868.
The product of its (nonzero) digits is 64512, while the sum is 39.
The spelling of 13008844173 in words is "thirteen billion, eight million, eight hundred forty-four thousand, one hundred seventy-three".
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