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130100011022 = 265050005511
BaseRepresentation
bin111100100101010010…
…0001010000000001110
3110102210220010022221202
41321022210022000032
54112421100323042
6135433410425502
712253666563452
oct1711244120016
9412726108852
10130100011022
11501a2078973
122126a292292
13c364820357
1464228a0662
1535b6a1b632
hex1e4a90a00e

130100011022 has 4 divisors (see below), whose sum is σ = 195150016536. Its totient is φ = 65050005510.

The previous prime is 130100011007. The next prime is 130100011031. The reversal of 130100011022 is 220110001031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 220110001031 = 892473146079.

It is a junction number, because it is equal to n+sod(n) for n = 130100010994 and 130100011012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32525002754 + ... + 32525002757.

It is an arithmetic number, because the mean of its divisors is an integer number (48787504134).

Almost surely, 2130100011022 is an apocalyptic number.

130100011022 is a deficient number, since it is larger than the sum of its proper divisors (65050005514).

130100011022 is an equidigital number, since it uses as much as digits as its factorization.

130100011022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65050005513.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 130100011022 its reverse (220110001031), we get a palindrome (350210012053).

Subtracting 130100011022 from its reverse (220110001031), we obtain a palindrome (90009990009).

The spelling of 130100011022 in words is "one hundred thirty billion, one hundred million, eleven thousand, twenty-two".

Divisors: 1 2 65050005511 130100011022