13010004310441 has 2 divisors, whose sum is σ = 13010004310442. Its totient is φ = 13010004310440.

The previous prime is 13010004310363. The next prime is 13010004310463. The reversal of 13010004310441 is 14401340001031.

It is a happy number.

It is an a-pointer prime, because the next prime (13010004310463) can be obtained adding 13010004310441 to its sum of digits (22).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12829864334400 + 180139976041 = 3581880^2 + 424429^2 .

It is an emirp because it is prime and its reverse (14401340001031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13010004310441 - 2⁷ = 13010004310313 is a prime.

It is a super-2 number, since 2×13010004310441² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13010004310141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505002155220 + 6505002155221.

It is an arithmetic number, because the mean of its divisors is an integer number (6505002155221).

Almost surely, 2^{13010004310441} is an apocalyptic number.

It is an amenable number.

13010004310441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010004310441 is an equidigital number, since it uses as much as digits as its factorization.

13010004310441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13010004310441 its reverse (14401340001031), we get a palindrome (27411344311472).

The spelling of 13010004310441 in words is "thirteen trillion, ten billion, four million, three hundred ten thousand, four hundred forty-one".