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13010020013 = 44382135771
BaseRepresentation
bin11000001110111010…
…10010011010101101
31020120200122111100002
430013131102122231
5203121031120023
65550545514045
7640254226334
oct140735223255
936520574302
1013010020013
1155768a9661
122631042925
1312c449c6c3
148b5c16d1b
15512280b28
hex3077526ad

13010020013 has 8 divisors (see below), whose sum is σ = 13055635296. Its totient is φ = 12964478800.

The previous prime is 13010019961. The next prime is 13010020019. The reversal of 13010020013 is 31002001031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010020013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13010019976 and 13010020003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13010020019) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 345818 + ... + 381588.

It is an arithmetic number, because the mean of its divisors is an integer number (1631954412).

Almost surely, 213010020013 is an apocalyptic number.

It is an amenable number.

13010020013 is a deficient number, since it is larger than the sum of its proper divisors (45615283).

13010020013 is an equidigital number, since it uses as much as digits as its factorization.

13010020013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37035.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13010020013 its reverse (31002001031), we get a palindrome (44012021044).

The spelling of 13010020013 in words is "thirteen billion, ten million, twenty thousand, thirteen".

Divisors: 1 443 821 35771 363703 15846553 29367991 13010020013