130101011133 has 4 divisors (see below), whose sum is σ = 173468014848. Its totient is φ = 86734007420.

The previous prime is 130101011111. The next prime is 130101011147. The reversal of 130101011133 is 331110101031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130101011133 - 2³² = 125806043837 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130101011153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21683501853 + ... + 21683501858.

It is an arithmetic number, because the mean of its divisors is an integer number (43367003712).

Almost surely, 2^130101011133 is an apocalyptic number.

It is an amenable number.

130101011133 is a deficient number, since it is larger than the sum of its proper divisors (43367003715).

130101011133 is an equidigital number, since it uses as much as digits as its factorization.

130101011133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43367003714.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 130101011133 its reverse (331110101031), we get a palindrome (461211112164).

The spelling of 130101011133 in words is "one hundred thirty billion, one hundred one million, eleven thousand, one hundred thirty-three".