1301011120031 has 4 divisors (see below), whose sum is σ = 1486869851472. Its totient is φ = 1115152388592.

The previous prime is 1301011119983. The next prime is 1301011120043. The reversal of 1301011120031 is 1300211101031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1301011120031 is a prime.

It is a super-2 number, since 2×1301011120031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301011119988 and 1301011120015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301011120081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92929365710 + ... + 92929365723.

It is an arithmetic number, because the mean of its divisors is an integer number (371717462868).

Almost surely, 2^{1301011120031} is an apocalyptic number.

1301011120031 is a deficient number, since it is larger than the sum of its proper divisors (185858731441).

1301011120031 is an equidigital number, since it uses as much as digits as its factorization.

1301011120031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185858731440.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1301011120031 its reverse (1300211101031), we get a palindrome (2601222221062).

The spelling of 1301011120031 in words is "one trillion, three hundred one billion, eleven million, one hundred twenty thousand, thirty-one".