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1301012330117 is a prime number
BaseRepresentation
bin10010111011101010011…
…000001011011010000101
311121101010210020011002012
4102323222120023122011
5132303433124030432
62433402105224005
7162665204225213
oct22735230133205
94541123204065
101301012330117
114618355a7855
1219018a492005
13958b9a60946
1446d7dbc5cb3
1523c97c3ecb2
hex12eea60b685

1301012330117 has 2 divisors, whose sum is σ = 1301012330118. Its totient is φ = 1301012330116.

The previous prime is 1301012330081. The next prime is 1301012330159. The reversal of 1301012330117 is 7110332101031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1011138846916 + 289873483201 = 1005554^2 + 538399^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301012330117 - 212 = 1301012326021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1301012330092 and 1301012330101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301012330417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650506165058 + 650506165059.

It is an arithmetic number, because the mean of its divisors is an integer number (650506165059).

Almost surely, 21301012330117 is an apocalyptic number.

It is an amenable number.

1301012330117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301012330117 is an equidigital number, since it uses as much as digits as its factorization.

1301012330117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 1301012330117 its reverse (7110332101031), we get a palindrome (8411344431148).

The spelling of 1301012330117 in words is "one trillion, three hundred one billion, twelve million, three hundred thirty thousand, one hundred seventeen".